81t^2-18t+1=0

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Solution for 81t^2-18t+1=0 equation: 



81t^2-18t+1=0

a = 81; b = -18; c = +1;
Δ = b2-4ac
Δ = -182-4·81·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{18}{162}=1/9$

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